Question

train runs at 40 kmph and destination late by 11 minutes but if it runs at 50k and it is late by 5 minute only find the distance to be covered by train​

Answer 1

Answer:

20 Km

Step-by-step explanation:

.................... "First Method".................

Let the correct time = x

And correct speed = y

Actual distance covered = xy

If it run by 40 km/h it is late by 11min

So we have

40×((x+11)/60) = xy

(40x+440)/60 = xy ……..(1)

If it run by 50km/h it is late by 5 minutes

So we have

50×((x+5)/60) = xy

(50x+250)/60=xy……….(2)

subtract (2) from(1)

-10x +190/60 = 0

x = 190/600

So it will take 19 minutes to complete the journey.

Put value in equation (2)

(950+250)/60 = xy

xy = 20

So it will cover 20 km in each case.

………………………"Second Method"…………………..

…………………………………………………………………………..

Let distance covered = x

And time = y.

time = distance /speed

So we have

x/40 = y-11/60

x = 40y-22/3

x-40y = 22/3

multiply by 5,

5x-200y = 110/3………………..…(1)

Now again time = distance / speed

So we have

x/50= y-5/60

x-50y=25/6

multiply by 4

4x-200y =100/6

4x-200y=50/3…………………….(2)

sub ( 2 ) from (1)

x = (110-50)/3

x = 20

So distance is 20 km