Question

train started from rest attains a velocity of 108 km per hour in 2
minutes As given the acceleration to be uniform find the value of acceleration and distance covered

Answer 1

here is your answer hope you tell you

Answer 2

Train starts from rest so the initial velocity(u)=0m/s

Final velocity(v) =108km/hr=108×5/18m/s
=30m/s

Time =2min=120sec

Now acceleration =v-u÷t=30-0/120=0.25m/s^2

using the eq. of motion

s=ut+1/2at2=(0×120) + (1/2×0.25×120^2)= 0+1800m=1800m