train starting from a railway station and moving with uniform acceleration attains a speed 40 km per hour in 10 minutes find its acceleration
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Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
Initial velocity (u) = 0
Final velocity (v)=40km/hr
= 40 multiple by 5/18 m/s
= 100/9
=11.11 m/s
Time (t) = 10 min
= 10 multiple with 60 s
= 600 s
Therefore
Acceleration = final velocity — initially velocity / time taken
=11.11 — 0 / 600 m/s sq
= 0.0185 m/s sq
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0
Answer:
it's the right answer....
ok thanks
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