Question

train starting from a railway station and moving with uniform acceleration attains a speed 40 km per hour in 10 minutes find its acceleration​

Answer 1

Answer:

0.0185m/second square

Explanation:

As the train started from a railway station, so initial velocity of train, u = 0

Final velocity of train, v = 40 kmph

Final velocity, v = 40 × 5/18 = 11.11 m/s

Assuming uniform acceleration of ‘a’ m/second square

Time taken by train to get it's final velocity, t = 10 minutes = 600 seconds

Using first equation of motion,

V = u + at

11.11 = 0 + a×600

a = 11.11/600 = 0.0185 m/second square.

So, required acceleration , a = 0.0185 m/second square.

Answer 2

Answer:

→ Acceleration : 0.018 ms^-2

Step-by-step explanation:

Given,

Initial velocity (u) = 0

Final velocity (v) = 40 km/h = 11.11 m/s

Time (t) = 10 m = 600 s

[How we got final velocity → v = 40000/3600 = 11.11 m/s]

★ Acceleration : v - u/t

= (11.11 - 0) m/s / 600 s

= 0.018 m/s² or 0.018 ms^-2

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