Question

train starting from a railway station and moving with a uniform acceleration attains a speed 40kmph in 10mins find the acceleration ?

ANSWER at correctly ​

Answer 1

Answer:

Given parameters

Initial velocity (u) = 0

Final velocity (v) = 40 km/h

v = 40 × (5/18)

v = 11.1111 m/s

Time (t) = 10 minute

t = 60 x 10

t = 600 s

Acceleration (a) =?

Consider the formula

v = u + at

11.11 = 0 + a × 600

11,11 = 600 a

a = 11.11/600

a = 0.0185 ms-2

Answer 2

Let u= initial velocity

v= final velocity

t= time

a= acceleration

GIVEN:

u= 0 (because it is starting from rest)

v= 40 km/h= 11.1 m/s

t= 10 minutes = 600 seconds

a= v- u/t

$= \frac{11.1 - 0}{600} \\ \\ = \frac{11.1}{600} \\ \\ = 0.0185 \: {m \: s}^{ - 2}$