Question

train starting from rest moves with uniform acceleration attains a speed of 40 kilometre per hour in 10 minutes find its acceleration​

Answer 1

Given,

$u = 0 \:{ms}^{ - 1}$

$v = 40 {kmh}^{ - 1}$

for coverting it to

${ms}^{ - 1}$

multiply by

$\frac{5}{18}$

$v = 40 \times \frac{5}{18} = \frac{100}{9} = 33.33 {ms}^{ - 1}$

$a = \frac{v - u}{t}$

putting the values,we get

$a = \frac{33.33 - 0}{10 \times 60}$

multiplied 10 minutes by 60 to convert time in seconds

$a = 0.055 {ms}^{ - 2}$