Question

train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 5 minutes calculate its acceleration. answer it by ur own don't copy.​

Answer 1

⭐《ANSWER》

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↪Actually welcome to the concept of the KINEMATICS

↪Basically we know that , the Rate of change of Velocity is termed as the Uniform Acceleration

↪So from the , First equation of motion , we get as ,

〽a = v - u / t

↪since here , we are given with the ,

↪As train starts from rest , so here , Initial Velocity ( U) = 0 ,

↪time = 5 mins = 300 seconds ,

↪The Final velocity in SI UNIT will be as ,

↪36 * 5/18 = 10 m/s

↪so we get as ,

↪a = 10 - 0 / 300

⭐a = 10/ 300 = 1/30 = 0.033 m/s^2

Answer 2

Answer0.3m/s raised to the power 2

Explanation:u=0

v=36km/h= 36×5\18 = 10m/s

T = 5 minutes

1 minute = 1×60

5 minutes = 5×60 = 300sec.

a = v-u/t

a = 10-0/300

a = 0.3m/s raised to the power 2.