Physics, asked by aakriti5055, 11 months ago

train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 5 minutes calculate its acceleration. answer it by ur own don't copy.​

Answers

Answered by Anonymous
48

⭐《ANSWER》

\huge\mathfrak{\underline {\underline\pink {ANSWER}}}

↪Actually welcome to the concept of the KINEMATICS

↪Basically we know that , the Rate of change of Velocity is termed as the Uniform Acceleration

↪So from the , First equation of motion , we get as ,

〽a = v - u / t

↪since here , we are given with the ,

↪As train starts from rest , so here , Initial Velocity ( U) = 0 ,

↪time = 5 mins = 300 seconds ,

↪The Final velocity in SI UNIT will be as ,

↪36 * 5/18 = 10 m/s

↪so we get as ,

↪a = 10 - 0 / 300

⭐a = 10/ 300 = 1/30 = 0.033 m/s^2


aakriti5055: thanks sir
Anonymous: no sir !!^_
Sonyahota: sir who
gureetpreet: good
gureetpreet: sir
shahid2641: very good
Answered by Jassi1212
21

Answer0.3m/s raised to the power 2

Explanation:u=0

v=36km/h= 36×5\18 = 10m/s

T = 5 minutes

1 minute = 1×60

5 minutes = 5×60 = 300sec.

a = v-u/t

a = 10-0/300

a = 0.3m/s raised to the power 2.


Sonyahota: hi
Sonyahota: I love you
gureetpreet: i love you too
gureetpreet: sony
aakriti5055: thanks for answering sir
hemant8518: right
Similar questions