train starting from stationary position and moving with uniform acceleration attains a speed of 36 km per hour in 5 minutes calculate its acceleration. answer it by ur own don't copy.
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48
⭐《ANSWER》
↪Actually welcome to the concept of the KINEMATICS
↪Basically we know that , the Rate of change of Velocity is termed as the Uniform Acceleration
↪So from the , First equation of motion , we get as ,
〽a = v - u / t
↪since here , we are given with the ,
↪As train starts from rest , so here , Initial Velocity ( U) = 0 ,
↪time = 5 mins = 300 seconds ,
↪The Final velocity in SI UNIT will be as ,
↪36 * 5/18 = 10 m/s
↪so we get as ,
↪a = 10 - 0 / 300
⭐a = 10/ 300 = 1/30 = 0.033 m/s^2
aakriti5055:
thanks sir
Answered by
21
Answer0.3m/s raised to the power 2
Explanation:u=0
v=36km/h= 36×5\18 = 10m/s
T = 5 minutes
1 minute = 1×60
5 minutes = 5×60 = 300sec.
a = v-u/t
a = 10-0/300
a = 0.3m/s raised to the power 2.
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