train starts from rest and accelerates at a rate of 1..m/s. Calculate the velocity in km/hr at the end
of 375m
Answers
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0
Answer:
98.6 kmph
Explanation:
Use equation of motion
v² - u² = 2aS
v = sqrt(u² + 2aS)
= sqrt(0² + (2 × 1 × 375))
= sqrt(750) m/s
= 27.4 m/s
= 27.4 × 18/5 kmph
= 98.6 kmph
Answered by
0
use the equations of motion
v² - u² = 2 as
v² = 2*1*375 = 750
v = 27.4 m/s
27.4 * 18/5 = 98.4 km/hr
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