Question

train starts from rest and accelerates at a rate of 1..m/s. Calculate the velocity in km/hr at the end
of 375m​

Answer 1

Answer:

98.6 kmph

Explanation:

Use equation of motion

v² - u² = 2aS

v = sqrt(u² + 2aS)

= sqrt(0² + (2 × 1 × 375))

= sqrt(750) m/s

= 27.4 m/s

= 27.4 × 18/5 kmph

= 98.6 kmph

Answer 2

use the equations of motion

v² - u² = 2 as

v² = 2*1*375 = 750

v = 27.4 m/s

27.4 * 18/5 = 98.4 km/hr