Question

train travelling at a speed of 90 km/hr. Brakes are applied so as to produce a uniform retardation of 0.5 ms^ -2. Find how for the train goes before it stops. *​

Answer 1

Answer:

Given:-

Initial velocity (u) = 90km/hr = 25m/s

Final velocity (v) = 0

Accleration = 0.5m/s^2

To find

Distance

By applying v^2-u^2 = 2as

0^2 - 25^2 = 2×0.5×s

625 = 1s

S = 625/1

S = 625m.