train travels from city A to B , when it go from A to B then its speed is 30m/s and when it is coming back then its speed is 40m/s then find its average speed is approximately
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32 m/s this is the correct answer
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hey mate good evening hope you had a nice day here is your answer
Total time taken by the body while going from A→B and then from B→A ist_(1)+t_(2) =(AB)/v +v_(1) +(BA)/v_(2) =AB [1/(40) +1/(60)] =(AB)/(24) sTotadistancetravel≤d= AB +BA =2 ABAvera≥speed,v_(av) =(2 AB)/(t_(1) +t_(2)) =(2AB)/((AB//24)) =48 ms^(1)Displacementofbody∈time(t1+t2)=0
[:. the body returns to its initial
position after time (t_(1) +t_(2))]Avera≥velocity,
v→av=displacementt1+t2=0t1+t2−0
Step-by-step explanation:
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