train was moving with initial speed 60 km/hr. Suddenly the driver decided to move with an acceleration of 5 m/s2 . Find the distance travelled by the train in 10 second
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Answered by
0
Answer:
0.416 km
Explanation:
u = 60km/h = 100/6 m/s
a = 5m/S2
t = 10 sec
So by Newton's second eq of motion
s = ut + 1/2 at^2
= 100/6*10 + 1/2 * 5*(10)^2
= 1000/6 + 250
= 1000 + 1500 /6
= 2500/6
= 416.6667 m or 0.416 km
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Answered by
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Answer:
Ur answer is 110 m/s
Explanation:
Acceleration = final velocity - initial velocity/time taken to accelerate
A = u-v/t
5m/s^2 = u - 60m/s / 10 sec
5 × 10 = u - 60
50 = u - 60
u. = 50 + 60
u. = 110
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