Question

Train x and train y runs between sirsa to kolkata. train x starts at 10.07am from sirsa and after 36min train y starts from kolkata. train y meets train x after 5hours48minutes of starting and the speed of train x is 105 km/hour.If the total distance between Sirsa and kolkata is 1020km, then find the speed of train y? ​

Answer 1

Step-by-step explanation:

Suppose the total distance is x,

Time taken by trains to meet = t

if speeds be s1 and s2, and they meet after time t,

=> s1*t + s2*t =x (eqn 1)

Train A takes total t+9 hours to travel x with speed s1,

=> s1(t+9)=x (eqn 2)

for train B, total time t+16

=> s2(t+16)=x (eqn 3)

9*s1= t*s2 (equate eqn 1 and 2)

t*s1= 16*s2 (equate eqn 1 and 3)

divide,

9/t= t/16 => t*t= 9*16

substitute t,

=> s1/s2= sqre-root (16/9)