Train x starts from point a for point b at the point a and b are 300 km apart. The trains are moving at a constant speed atleast at 25km/h. The trains meet each other 3 hours after they start. If the faster train takes atleast 2 more hours to reach the destination. By which time will the slower train have definitely reached its destination? (ignoring te length of trains in crossing?
Answers
The slower train will have definitely reached at its destination 7.5 hours after the start.
Explanation:
Suppose the speed of train x is 'p' km/h and the speed of train y is 'q' km/h
Total speed = Distance between to points / The time taken by two trains to meet each other
p + q = 300 / 3 = 100 km/h
=> The time taken by fastest train to reach its destination:
T = 3 + 2 = 5 hr
For instence, the speed of lower train is 40 km per hour.
Thus, the time taken by slow train"
t = Total distance / speed
= 300 / 40
= 7.5 hr
Hence, the slower train will have definitely reached at its destination 7.5 hours after the start.
Learn more:
Q:1 If a train runs at 40kmph it reaches its destination late by 11 minutes. but if it runs at 50kmph it is late by 5 minutes only.find the distance to be covered by the train?
Click here: https://brainly.in/question/233711
Q:2 The distance between two towns is 300 km two cars start simultaneously from these towns and move towards each other the speed of one car is more than the other by 7km per hour if the distance between the cars after 2 hours in 34km find the speed of thecar.
Click here: https://brainly.in/question/1790653
Answer:
Explanation:
Let speeds : a = slower train , b= faster train
then a+b = 300/ 3=100km/h
also it is given
b takes 2 more hour to complete journey
=> time(b) = 2+3=5
then b × 5 = 300 ( coz , T × S = D)
then b = 60 km/hr
then a= 100- 60 = 40km/hr
=> Time (a) = 300/40=7.5 hr