Question

trans form the following equation into (a)slope intercept form (b)intercept from and (c)normal from 4x-3y+12=0
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Answer 1

Step-by-step explanation:

4x-3y+13=0

(1) slope intercept from

4x+12=3y

y=4\3 x+12/3=4/3x+y

intercept fromy axis

4x=3y-12

n=3/4y _12/4=3/4y-3

normal form

4x-3y+12=0

4x/3 -3x/5+12/5=0

4x/5-3y/5=-12/5

dividing by

[4square +3square=16+9=25=5] is the normal form