Question

transform the equation 3x+4y+12=0 into (a) slope intercept (b) intercept from (c) normal from​

Answer 1

Answer:

$3x + 4y + 12 = 0 \\ 4y = - 3x - 12 \\ y = \frac{ - 3x}{4} -3 \: \: \: ...(1) \\ on \: comparing \: equation \: (1) \: with \: y = mx + c \\ we \: get : \\ slope \: m = cofficient \: of \: x = \frac{ - 3}{4} \\ y - intercept \: c= constant \: term = - 3$