Question

Transform the equation 6/x + (x - 3) /5 = 2 into the standard dorm of quadratic equation

Answer 1

Solution:-

Standard form of quadratic equation is

ax² + bx + c = 0

Now,

${ \huge{\dashrightarrow{ \bf{ \frac{6}{x} + \frac{(x - 3)}{5} = 2}}}}$

${ \huge{\dashrightarrow{ \bf{ \frac{6 \times 5}{x \times 5} + \frac{(x - 3) \times x}{5 \times x} = 2}}}}$

${ \huge{\dashrightarrow{ \bf{ \frac{30}{ 5x} + \frac{{x}^{2} - 3x}{5 x} = 2}}}}$

${ \huge{\dashrightarrow{ \bf{ \frac{{x}^{2} - 3x + 30}{ 5x} = 2}}}}$

Multiply both side by 5x, we get

${ \huge{\dashrightarrow{ \bf{ {{x}^{2} - 3x + 30} = 10 x}}}}$

${ \huge{\dashrightarrow{ \bf{ {{x}^{2} - 3x } - 10 x + 30} = 0}}}$

${ \huge{\dashrightarrow{ \bf{ {{x}^{2} } - 13 x + 30} = 0}}}$

Hence, standard quadratic form of equation is x² - 13x + 30 = 0.