Question

transform the following equation into normal form 4x-3Y+12=0​

Answer 1

Answer:

$4/5x−3/5y=-12/5$

Step-by-Step explanation:

Normal form

4x−3y+12=0

Dividing by

√[4^2+3^2]

⇒√16+9

⇒√25=5]

$4/5x−3/5y=-12/5$

is the normal form