Question

Transform the following equations into slope intercept form, intercepts form and nor- mal form i) x + y + 2 = 0)
ii) x + y - 2 = 0
iii) 3x + y = 4
iv) (3x + y + 10 = 0)
very urgent please help​

Answer 1

Answer:

4x−3y+13=0

(1) slope intercept from

4x+12=3y

y=

3

4

x+

3

12

⇒

3

4

x+4

(2) Intercept from

[from (1)] which intercept at y−axis

equation for x which intercept at x−axis

4x=3y−12

n=

4

3

y−

4

−12

⇒

4

3

y−3

Intercept at x−axis ⇒

x=

4

3

y−3

Intercept at y−axis ⇒

y=

3

4

x+4

(3) Normal form

4x−3y+12=0

⇒

3

4x

−

5

3y

+

5

12

=0

⇒

5

4x

−

5

3y

=

5

−12

Dividing by

[

4

2

+3

2

⇒

16+9

⇒

25

=5]

is the normal form