Transform x+y+1=0 into coordinate form
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Formula used:
Normal form of straight line is
x\:cos\:\alpha+y\:sin\:\alpha=p
Given line is x+y+1=0
It can be written as
- x - y =1
divide both sides by \sqrt{(-1)^2+(-1)^2}=\sqrt{2}, we get
x(\frac{-1}{\sqrt{2}})+y(\frac{-1}{\sqrt{2}})=\frac{1}{\sqrt{2}}\\\\x.cos(\frac{5\pi}{4})+y.sin(\frac{5\pi}{4})=\frac{1}{\sqrt{2}}
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