Chemistry, asked by alkapapanai1985, 9 months ago

Translate the following statement into chemical equation and then balance the equation:-

a) hydrogen sulphide gas burns in air to give water and Sulphur dioxide

b) Phosphorus burns in oxygen to give Phosphorus pentoxide

c) carbon disulfide burns in air to give carbon dioxide and Sulphur dioxide

d) aluminium metal the places iron from ferric oxide giving Aluminium oxide and iron

e) sulphate Barium Chloride reacts with zinc sulphate to give zinc chloride and Barium sulphate


Answers

Answered by StarrySoul
30

Solution :

a) Hydrogen sulphide gas burns in air to give water and Sulphur dioxide

→ Here,

• Reactants : Hydrogen Sulphide and Oxygen

• Products : Water and Sulphur Dioxide

Equation formed :

 \sf \: H_2S(g) + O_2  (g)\rightarrow \: H_2 O (l)+ SO_2(g)

Balanced Equation :

 \sf \: 2H_2S(g) + 3O_2  (g)\rightarrow \: 2H_20 (l)+ 2SO_2(g)

b) Phosphorus burns in oxygen to give Phosphorus pentoxide

→ Here,

• Reactants : Phosphorus and Oxygen

• Product : Phosphorus Pentoxide

Equation formed :

\sf P(s) + O_{2} (g) \longrightarrow P_{4} O_{10} (s)

Balanced Equation:

\sf P_{4} (s) + 5O_{2} (g) \longrightarrow 2P_{2} O_{5}

c) Carbon disulfide burns in air to give carbon dioxide and Sulphur dioxide

→ Here,

• Reactants : Carbon disulfide and oxygen

• Products : Carbon Dioxide and Sulphur Dioxide

Equation formed :

 \sf \: CS_2(g) + O_2(g) \rightarrow CO_2(g) + S_20 (g) \:

Balanced Equation :

 \sf \: CS_2(g) + 3O_2(g) \rightarrow CO_2(g) + 2S_20 (g) \:

d) Aluminium metal replaces iron from ferric oxide giving Aluminium oxide and iron.

→ Here,

• Reactants : Aluminum and Ferric Oxide

• Products : Aluminum Oxide and Iron

Equation formed :

 \sf \: Al(s) + Fe_2O_3(s) \rightarrow Al_2O_3(s) + Fe (s)

Balanced Equation :

 \sf \: 2Al(s) + Fe_2O_3(s) \rightarrow Al_2O_3(s) + 2Fe (s)

e) Barium Chloride reacts with zinc sulphate to give zinc chloride and Barium sulphate.

→ Here,

• Reactants : Barium Chloride and Zinc Sulphate

• Products : Zinc Chloride and Barium Sulphate

Equation formed :

 \sf \: BaCl_2(s)  +  ZnSO_4(s)    \rightarrow      ZnCl_2(s) + BaSO_4(s)

This equation is already balanced.

Answered by SarcasticAngel
17

Answer:

Solution :

a) Hydrogen sulphide gas burns in air to give water and Sulphur dioxide

→ Here,

• Reactants : Hydrogen Sulphide and Oxygen

• Products : Water and Sulphur Dioxide

Equation formed :

\sf \: H_2S(g) + O_2 (g)\rightarrow \: H_2 O (l)+ SO_2(g)H

2

S(g)+O

2

(g)→H

2

O(l)+SO

2

(g)

Balanced Equation :

\sf \: 2H_2S(g) + 3O_2 (g)\rightarrow \: 2H_20 (l)+ 2SO_2(g)2H

2

S(g)+3O

2

(g)→2H

2

0(l)+2SO

2

(g)

b) Phosphorus burns in oxygen to give Phosphorus pentoxide

→ Here,

• Reactants : Phosphorus and Oxygen

• Product : Phosphorus Pentoxide

Equation formed :

\sf P(s) + O_{2} (g) \longrightarrow P_{4} O_{10} (s)P(s)+O

2

(g)⟶P

4

O

10

(s)

Balanced Equation:

\sf P_{4} (s) + 5O_{2} (g) \longrightarrow 2P_{2} O_{5}P

4

(s)+5O

2

(g)⟶2P

2

O

5

c) Carbon disulfide burns in air to give carbon dioxide and Sulphur dioxide

→ Here,

• Reactants : Carbon disulfide and oxygen

• Products : Carbon Dioxide and Sulphur Dioxide

Equation formed :

\sf \: CS_2(g) + O_2(g) \rightarrow CO_2(g) + S_20 (g) \:CS

2

(g)+O

2

(g)→CO

2

(g)+S

2

0(g)

Balanced Equation :

\sf \: CS_2(g) + 3O_2(g) \rightarrow CO_2(g) + 2S_20 (g) \:CS

2

(g)+3O

2

(g)→CO

2

(g)+2S

2

0(g)

d) Aluminium metal replaces iron from ferric oxide giving Aluminium oxide and iron.

→ Here,

• Reactants : Aluminum and Ferric Oxide

• Products : Aluminum Oxide and Iron

Equation formed :

\sf \: Al(s) + Fe_2O_3(s) \rightarrow Al_2O_3(s) + Fe (s)Al(s)+Fe

2

O

3

(s)→Al

2

O

3

(s)+Fe(s)

Balanced Equation :

\sf \: 2Al(s) + Fe_2O_3(s) \rightarrow Al_2O_3(s) + 2Fe (s)2Al(s)+Fe

2

O

3

(s)→Al

2

O

3

(s)+2Fe(s)

e) Barium Chloride reacts with zinc sulphate to give zinc chloride and Barium sulphate.

→ Here,

• Reactants : Barium Chloride and Zinc Sulphate

• Products : Zinc Chloride and Barium Sulphate

Equation formed :

\sf \: BaCl_2(s) + ZnSO_4(s) \rightarrow ZnCl_2(s) + BaSO_4(s)BaCl

2

(s)+ZnSO

4

(s)→ZnCl

2

(s)+BaSO

4

(s)

This equation is already balanced.

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