Trapezium ABCD AB||CD angle a = y+60 angle b= x + 60 angle c = 3x -40 angle d= 3y - 80 Find each angle of trapezium
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in trapezium all angle are 360 degree
angle a+angleb+anglec+angled =360
y+60+x+60+3x-40+3y-80=360
4y+4x+120-120=360
4(x+y)=360
x+y=90
x=90-y (1)
Now angle b+angle c=180
x+60+3x-40=180
4x+20=180 (2)
put(1)in(2)
4(90-y)+20=180
360-4y+20=180
380-4y=180
-4y=-200
y=50 (3)
put in (1)
x=40 (4)
Put in all angles
angle A=110,angle B=100 angle C=80 angle D=70
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Answer:
y = 50 x = 40
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Step-by-step explanation:
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