Question

trapezium ABCD in which ab is parallel to CD are 2 X + 50 and 2x - 10 find the measures of the angles​

Answer 1

Answer:

120° & 60°

Step-by-step explanation:

trapezium ABCD in which ab is parallel to CD are 2 X + 50 and 2x - 10 find the measures of the angles​

2X + 50 + 2X - 10 = 180°

=> 4X = 140°

=> X = 35°

2X + 50 = 2*35 + 50 = 120°

2X - 10 = 2 *35  - 10 = 60°

Meausre of Angles are 120° & 60°

Answer 2

Answer:

60° and 120°

Step-by-step explanation:

2x + 50 + 2x - 10 = 180°

4x + 40 = 180°

4x = 180 - 40

4x = 140

x = 140/4

x = 35°

2x + 50 = 2 × 35 + 50

= 70 + 50

= 120°

2x - 10 = 2 × 35 -10

= 70 - 10

= 60°