Trapezium ABCD in which AB parallel CD ,AB=8cm,BC=6cm , CD=4cm and angle B=60 degree
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Step-by-step explanation:
=> It is given that In Trapezium ABCD, AB || CD,
AB = 8 cm,
BC = 6cm,
CD = 4cm and
∠B = 60°
=> But, In isosceles trapezium, non parallel sides are equal in length
hence, CD = AD = 4 cm
and ∠A = ∠B = 60° and
∠C = ∠D
and ∠B + ∠C = 180°
∠C = 120°
and ∠C = ∠D = 120°
lets construct a trapezium :
=> Draw a line AB = 8 cm
=> Construct angle 60° at A and at B as ∠A = ∠B = 60°
=> Lets take radius 6cm and cut the angle ray as take center A than it cut at D and take center B than it cut at C. (As AD = BC = 6cm)
=> Construct angle of 120° at C and that ray meet at D as CD = 4 cm.
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