Trapezium PQRS lies inside the rhombus PQTU. The area of rhombus is
16,38 m'and area of shaded portion is 8.14 m. Find the area of trapezium.
Also, find the height of trapezium if PQ=0.6 m and RS = 43 cm.
Answers
Given : Trapezium PQRS lies inside the rhombus PQTU.
The area of rhombus is 16,38 m² and area of shaded portion is 8.14 m².
PQ=0.6 and RS-43 cm
To Find : the area of trapezium
the height of trapezium
Solution:
Area of rhombus = 16.38 m²
area of shaded portion = 8.14 m²
Area of trapezium = Area of rhombus - area of shaded portion
=> Area of trapezium = 16.38 - 8.14
=> Area of trapezium = 8.24 m²
Area of trapezium = (1/2) (PQ + RS) * (height of trapezium )
PQ = 0.6 m , RS = 43 cm = 0.43
= (1/2)( 0.6 + 0.43) * (height of trapezium )
= (1/2)( 1.03) * (height of trapezium )
(1/2)( 1.03) * (height of trapezium ) = 8.24
=> height of trapezium = 16
height of trapezium = 16 m
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Given :
Trapezium PQRS lies inside the rhombus PQTU.
The area of rhombus is 16,38 m² and area of shaded portion is 8.14 m².
PQ=0.6 and RS-43 cm
To Find :
the area of trapezium
the height of trapezium
Solution:
Area of rhombus = 16.38 m²
area of shaded portion = 8.14 m²
Area of trapezium = Area of rhombus - area of shaded portion
=> Area of trapezium = 16.38 - 8.14
=> Area of trapezium = 8.24 m²
Area of trapezium = (1/2) (PQ + RS) * (height of trapezium )
PQ = 0.6 m , RS = 43 cm = 0.43
= (1/2)( 0.6 + 0.43) * (height of trapezium )
= (1/2)( 1.03) * (height of trapezium )
(1/2)( 1.03) * (height of trapezium ) = 8.24
=> height of trapezium = 16
height of trapezium = 16 m