Math, asked by aradhya235, 6 months ago

trapezium pqrs lies inside the room was speak cutie you the area of rhombus is 16.38 and area of shaded portion is 8.14 metre square find the area of trapezium also find the height of trapezium is PQ = 20.6 and rs equal to 43 CM​

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Answered by amitnrw
1

Given : Trapezium PQRS lies inside the rhombus PQTU.

The area of rhombus is 16,38 m² and area of shaded portion is 8.14 m².

PQ=0.6  and RS-43 cm

To Find :  the area of trapezium

 the height of trapezium  

Solution:

Area of rhombus =  16.38    m²

area of  shaded portion = 8.14 m²

Area of trapezium = Area of rhombus - area of  shaded portion

=> Area of trapezium = 16.38 - 8.14  

=> Area of trapezium = 8.24   m²

Area of trapezium = (1/2) (PQ + RS) * (height of trapezium )

PQ = 0.6 m  , RS = 43 cm = 0.43  

= (1/2)( 0.6 + 0.43) *  (height of trapezium )

=  (1/2)( 1.03) *  (height of trapezium )

(1/2)( 1.03) *  (height of trapezium ) = 8.24

=> height of trapezium = 16

height of trapezium = 16 m

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Answered by akshitanegi26
3

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Area of Rhombus = 16.38 m²

Area of shaded part = 8.14 m²

Area of trapezium = 16.38 - 8.14 = 8.24 m²

Area of trapezium = 1/2 (0.6+0.43) * height of trapezium.

1/2 * 1.03 * Height of trapezium = 8.24

Height of trapezium = 16 m.

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