Chemistry, asked by atharva1703, 6 months ago

Treatment of ammonia with excess of ethyl iodide will yield
(A) Diethyl amine
(B) Ethyl amine
(C) Triethyl amine
(D) Tetraethylammonium iodide

Answers

Answered by Anonymous

33

ur answer is d)

hope it helps......

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Answered by Anonymous

1

Answer:

(d) tetraethylammonium iodide

hope this helps you...

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