Question

trial and error method
b) 8y=48
c)2m/7=2

Answer 1

Answer:

b) 8y = 48

= y= 48/8

y = 6

c) 2m/7 =2

2m = 2 × 7

m = 14/2

m = 7

Step-by-step explanation:

We can take x = +/- 1,2,3,4,5,6,7 and try them as per the trial and error method

Answer 2

Answer:

1) If 8y=48, then y = 6

2) If 2m/7=2, then m = 7

Step-by-step explanation:

1) 8y=48

Put y = 1

LHS = 8y = 8(1) = 8 ≠  48

So, y = 1 is not a solution of 8y= 48

Put y = 2

LHS = 8y = 8(2) = 16 ≠  48

So, y = 2 is not a solution of 8y= 48

Put y = 3

LHS = 8y = 8(3) = 24 ≠  48

So, y = 3 is not a solution of 8y= 48

Put y = 4

LHS = 8y = 8(4) = 32 ≠  48

So, y = 4 is not a solution of 8y= 48

Put y = 5

LHS = 8y = 8(5) = 40 ≠  48

So, y =5 is not a solution of 8y= 48

Put y = 6

LHS = 8y = 8(6) = 48

So, y = 6 is  a solution of 8y= 48

2)2m/7=2

Put m = 1

LHS = 2m/7 = 2(1)/7 = 2/7  ≠  2

So, m = 1 is not a solution of 2m/7=2

Put m = 2

LHS = 2m/7 = 2(2)/7 = 4/7  ≠  2

So, m = 2 is not a solution of 2m/7=2

Put m = 3

LHS = 2m/7 = 2(3)/7 = 6/7  ≠  2

So, m = 3 is not a solution of 2m/7=2

Put m = 4

LHS = 2m/7 = 2(4)/7 = 8/7  ≠  2

So, m = 4 is not a solution of 2m/7=2

Put m = 5

LHS = 2m/7 = 2(5)/7 = 10/7  ≠  2

So, m = 5 is not a solution of 2m/7=2

Put m = 6

LHS = 2m/7 = 2(6)/7 = 12/7  ≠  2

So, m = 6 is not a solution of 2m/7=2

Put m = 7

LHS = 2m/7 = 2(7)/7 = 14/7  = 2

So, m = 7 is not a solution of 2m/7=2