Question

triangle ABC AC is equals to 15 CM n DE is parallel to BC if add upon AC is 3 cm find EC ​

Answer 1

$In\; the\; similar\; triangles,\; the\; sides\; are\; in\; proportion.\\AC/DF =BC/EF \\AC =12, BC = 18 and DF = 10\\Now\; plug\; in\; these\; values\; in\; the \;proportion\; and\; find\; the\; value\; EF\\12/10 = 18/EF\\Cross\; multiplying,\; we\; get\\12 EF = 18 *10\\12EF =180\\EF = 180/12\\EF = 15\\The length of EF is 15 cm.$

Answer 2

Answer:15

Step-by-step explanation: