Question

Triangle abc and triangle d e f are similar and their areas be respectively 64 cm square and 121 cm square if f is equal to 15.4 cm bc is equal to

Answer 1

Answer:

Step-by-step explanation:∆ABC~∆DEF...,..........given

Now,

By similar triangle theorem we get,

∆ABC2 /∆ DEF2 = BC2 / EF2

64/121 = BC2/(15.4)2

By taking square roots of both sides,

8/11= BC/15.4

By cross multiplication,

(15.4×8)/11 = BC

BC=11.2

therefore value of BC is 11.2 cm

Answer 2

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