Question

Triangle abc and triangle dbc are on the same base bc and on opposite sides of bc

Answer 1

Full question please

Answer 2

To Show :

∆ABD ≅ ∆ACD.

∆ABP ≅ △ACP

AP bisects ∠A as well as ∠D

AP is perpendicular bisector of BC .

Proof :

In △ABD AND △ACD

AB = AC [ GIVEN]

AD = AD [ COMMON ]

BD = CD [ GIVEN ]

Therefore, ∆ABD ≅ ∆ACD.[SSS]

2. In △ABP and △ ACP

AB = AC [ GIVEN ]

∠BAP = ∠CAP [ C.P.C.T ]

AP = AP [ COMMON ]

Therefore , △ABP ≅ △ACP [ SAS ]

Other parts referred as attachment..