Question

triangle ABC and triangle DBC are two isosceles triangle on the same base BC are vertex A and B are not the same side of BC if ad is extended to intersect BC at P show that triangle ABC congruent to triangle ACD second angle triangle ABC congruent to triangle ACP third AP bisector a as well as D is perpendicular bisector of BC
​

Answer 1

Answer:

the

the=13oo3

sa=5679^2return puch ha ha

Answer 2

hope this attachment helps you..!!