Question

triangle ABC and triangle DBC have common base BC . prove that A(∆ABC) upon A(∆DBC)=AO upon DO​

Answer 1

Step-by-step explanation:

it is proved by the property of:

it is proved by the property of:the ratio of the area of two triangles with equal bases is equal to the ratio of their corresponding heights.

i.e. h1/h2

areas proportionate to heights.

AO and DO are the corresponding heights of the given triangles.

where BC is their common base.

so it is proved that,

A(∆ABC) upon A(∆DBC)=AO upon DO

Answer 2

Explain easy method step by step