Triangle abc and triangle def are similar length of bc=4cm and ef=5cm the perimeter of triangle abc =80cm square the find the perimeter of triangle def
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ar ( ABC) / ar ( DEF) = BC ,EF . (by theorem)
80 ar (DEF) = 4/5
ar (DEF) = 80*5/4
ar (DEF) = 100 cm sq.
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