Question

triangle ABC, angle B = 30°, AB = 11 cm and BC = 60 cm. Find AC.​

Answer 1

$\huge\mathcal{Answer:}$

∠ABC = 30°

Side AB = 11 cm

Side BC = 60 cm

We have to find the length of AC.

By cosine rule in the ΔABC.

$b^{2}=a^{2}+c^{2}-2a.c.cosB$

Here AC = b

BC = a and side AB = c

Now we plug in the values of a, b, c and ∠B in the formula

b² = 3721 - 1143.15

b = √(2577.86)

b = 50.77 cm