Question

triangle ABC, Angle B is equal to Angle C and Angle A is equal to 100°
Find angle B ​​

Answer 1

Answer:

AB=AC

∠B=∠C          [Angles opposite to equal sides are equal]

In △ABC,

∠A+∠B+∠C=180o

100o+2∠B=180o

∠B=40o

Therefore,

∠B=∠C=40o

Answer 2

Answer:

${ \huge\fbox \pink {♥}\fbox \blue {A} \fbox\purple {N} \fbox \green{S} \fbox \red {W} \fbox \orange {E} \fbox{R} \fbox \gray{♥}}$triangle ABC, Angle B is equal to Angle C and Angle A is equal to 100°

AB=AC

∠B=∠C [Angles opposite to equal sides are equal]

In △ABC,

∠A+∠B+∠C=180

o

100

o

+2∠B=180

o

∠B=40

o

Therefore,

∠B=∠C=40

o