Question

Triangle abc, angle c=90 degree, tan a=1/ root 3. Prove that sin a* cos b+cos a*sin b=1

Answer 1

I Hope You Will Understand My Handwriting.:')

Answer 2

Answer:

Step-by-step explanation:

tanA=BC/AB=‌1/root 3

Thus BC=1 AB=root 3

In triangle ABC,

AB2+BC2=AC2

Thus AC=2(BY PYTHAGORAS THEORM)

SinAcosC+cosAsinC=1/2*1/2+root3 /2*root3/2

=1/4+3/4

=4/4

=1