Math, asked by ymandlik82, 2 months ago

triangle ABC are A 90 digree Triangle and D is it s median prove that triangle ABD is similar to triangle BDC​

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Answered by MrMonarque
27

Hello, Buddy!!

||GIVEN||

  • ABC is a triangle in which BD is a Median.

||TO PROVE||

  • ∆ABD ~ ∆BDC

||REQUIRED PROOF||

As, BD is a Median, AD = DC

[Median Of Triangle divides the opposite side into two equal parts]

BD ⊥ AC, ∠ADB = ∠BDC → 90°

In ∆ABD & ∆BDC

AD = DC [Proved Above]

∠ADB = ∠BDC [BD ⊥ AC]

BD = BD [Common Side]

By SAS Similarity Axiom

  • ∆ABD ~ ∆BDC

Hence, Proved.

Median:- A line sigment drawn from one vertex of a triangle to the mid point of opposite side, the line segment is known as Median of the Triangle.

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Hope It Helps You ✌️

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