triangle ABC are A 90 digree Triangle and D is it s median prove that triangle ABD is similar to triangle BDC
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Hello, Buddy!!
||GIVEN||
- ABC is a triangle in which BD is a Median.
||TO PROVE||
- ∆ABD ~ ∆BDC
||REQUIRED PROOF||
As, BD is a Median, AD = DC
[Median Of Triangle divides the opposite side into two equal parts]
BD ⊥ AC, ∠ADB = ∠BDC → 90°
In ∆ABD & ∆BDC
AD = DC [Proved Above]
∠ADB = ∠BDC [BD ⊥ AC]
BD = BD [Common Side]
By SAS Similarity Axiom
- ∆ABD ~ ∆BDC
Hence, Proved.
Median:- A line sigment drawn from one vertex of a triangle to the mid point of opposite side, the line segment is known as Median of the Triangle.
Hope It Helps You ✌️
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