triangle ABC b=90 AC =16 bc=8 c = -
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in a triangle given
ABC b=90 AC =16 bc=8
so here the triangle is a right anglrd triangle
and w.k.t
so here adj=8 and hyp=16
then
cos c= 8÷16
so cos c = 1÷2
cos c= cos 60 degrees
by removing the cos we get
c= 60
hence
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