Question

triangle ABC congruent to Triangle d e f their area are 64 CM and 100 CM respectively.if EF=12 CM then find the measure of BC​

Answer 1

Answer:

Theorem : The ratio of the area of two similar triangles is equal to the ratio of the squares of their corresponding sides .

We are given that ∆ abc ~ ∆ def and their areas are 64cm2 and 100cm2 respectively and ef=12cm

So,\frac{(bc)^2}{(ef)^2}=\frac{64}{100}(ef)2(bc)2=10064

\frac{(bc)^2}{(12)^2}=\frac{64}{100}(12)2(bc)2=10064

(bc)^2=\frac{64}{100} \times 12^2(bc)2=10064×122

(bc)^2=92.16(bc)2=92.16

bc = \sqrt{92.16}bc=92.16

bc=9.6 cm

Hence the measure of bc is 9.6 cm

#Learn more:

∆ ABC ~∆DEF and their areas are respectively 64cm2 and 121cm2 if EF=15.4cm then find BC