Question

triangle ABC, DE BC such that AD=Xcm, DB= (3X+4)cm, AE=
(X+3)cm and EC= (3X+19)cm. Find the value of x.
​

Answer 1

Step-by-step explanation:

DE∣∣BC

AD=x cm, DB=(3x+4)cm

AE=(x+3)cm and EC=(3x+19)cm

In ΔABC

DB

AD

=

EC

AE

(3x+4)

x

=

(3x+19)

(x+3)

3x

2

+19x−3x

2

−9x−4x=12

x=2

is it correct?