Triangle ABC has a right angle at B. Point D is the foot of the altitude from B. If AD = 3cm and DC = 4cm, then the area of the triangle ABC is : (1) 7√3 sq.cm (2)4√3 (3) 21 (4) 42 sq.cm
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perpendicular bisector is a line which cuts a line segment into two equal parts at 90°. So AC to be a perpendicular bisector of BD it must not only cut it at 90° (which it does) but also cut it into two equal parts. Now, in order AC to cut BD into two equal parts right triangle ABD must be isosceles, which, as it turns out after some math, it is not.
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