Question

triangle ABC has AB arm. The midpoint ofAB arm is E,D is a point on BC arm that BD=2DC. AD and CE intersect at P,point. The area of triangle PED is 5 cm square. what is the area of triangle ABC.
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Answer 1

Answer:

thank me plzz

Step-by-step explanation:

We know,

Using cosine rule

c

2

=b

2

+a

2

−2abcosC=b

2

+a

2

−2ab(

2

a

b

)

=b

2

+a

2

−4b

2

∴c

2

=a

2

−3b

2

⇒3b

2

=a

2

−c

2