Question

Triangle ABC has vertices A(–2, –3), B(–5, –3), and C(–4, –2). The triangle is rotated 90° counterclockwise around the origin.


What is the correct set of image points for triangle A’B’C’?
A’(3, 2), B’(3, 5), C’(2, 4)
A’(3, –2), B’(3, –5), C’(2, –4)
A’(–3, –2), B’(–3, –5), C’(–2, –4)
A’(–3, 2), B’(–3, 5), C’(–2, 4)

Answer 1

Answer:

S.P of 2nd Saree = Rs.3552

Given:

Nidhi purchased two sarees for Rs.2150 each

She sold one at loss of 8% and other at gain and she had a gain of Rs1230 on whole transaction

To find:

S.P of the 2nd Saree

Solution:-

C.P of 1st Saree=Rs.2150

Loss=8%

s.p =c.p \times \frac{100 - loss\%}{100}s.p=c.p×100100−loss%

= 2150 \times \frac{100 - 8}{100}=2150×100100−8

= 2150 \times \frac{92}{100}=2150×10092

= 1978=1978

S.P of 1st Saree=Rs. 1978

Now

Let 2nd Saree S.P be x

profit of Rs.1230

We know that

Total S.P-Total C.P=Total Profit

(1978 + x) - (2 \times 2150) = 1230(1978+x)−(2×2150)=1230

1978 + x - 4300 = 12301978+x−4300=1230

x - 2322 = 1230x−2322=1230

x = 1230 + 2322x=1230+2322

x = 3552x=3552

___________________

S.P of 2nd Saree =Rs. 3552