Question

triangle ABC if BC=AB B=80​

Answer 1

Answer:

Sorry but your question is not complete. But I think I have to find Angle A and Angle C

AB = BC

<A = <C [Angles opposite to equal sides are equal]

<A+<B+<C=180° [ASP]

<A+80°+<C=180°

2<A=100°

<A=100/2

<A=50°=<C

So angle A =50° and angle C= 50°

Step-by-step explanation:

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