Question

triangle ABC in which a b is equal to 6 CM AC = 8 cm and BAC is equal 50 degree

Answer 1

perimeter of triangle = sum of all sides
6+8+BC=50
14+BC=50
BC=50-14
BC=36 cm

Answer 2

Answer: All I can find is the area and the perimeter.

                         Area = 18 cm²  and Perimeter -= 20 cm

Step-by-step explanation:

             Given AB=6 and AC=8

                   Also the included angle ∠BAC is given as 50°

Area of any triangle = $\frac{1}{2}$×Product of two sides×Sin(Angle between them).

         =0.5×8×6×Sin(50°)

        =24×0.76604444311

        =18.38506663464=18

      Also the 3rd side can be found using the Cosine rule

                              which is $\frac{ c^{2}+b^{2}-a^{2}}{2bc}$=Cos(∠A)

Where AB=c and BC=a and AC=b

                                   ⇒$\frac{6^{2}+8^{2}-a^{2}}{2*8*6}$=Cos50°

                                   ⇒$\frac{100-a^{2}}{96}$=0.64278760968

                                   ⇒100-$a^{2}$=61.70761052928

                                   ⇒100-61.70761052928=$a^{2}$

                                   ⇒38.29238947072=$a^{2}$

                                   ⇒a=6.1888 ≅ 6

                        Therefore perimeter = 6+6+8 = 20