Question

triangle ABC is 90° triangle AB=BC=4cm find the length of AC
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Answer 1

Answer:

ac²=ab²+bc²

ac²=16 +16

ac=5.6

Answer 2

Step-by-step explanation:

We are given that in △ABC,∠=90o

tyhe sides of △ABC is given by

AB=x cm,BC=(4x+4)cm & 

AC=(4x+5) cm

From the pythagoras theorem,

AC2=AB2+BC2

So,

(4x+5)2−(x)2+(4x+4)2

16x2+40x+25=x2+16x2+22z−16

∴ 16x2+40x+25=17x2+32x+16

∴ x2−8x−9=0

∴ (x−9)(x+1)=0

∴ x=9 or x=−1

but distance cannot be negative 

So, x=9

Now, sides are AB=x=9 cm

BC=4(9)+4=40 cm

AC=4(9)+5=41 cm