Question

triangle ABC is a given triangle
Point D on ray ba is such that ad=ac.Ray ae is parallel to seg cd and intersects side bc in point E prove that ray AE is the bisector of angle BAC

Answer 1

Answer:

In △ABC, AD bisects ∠A

$∴ \frac{AC}{AB} = \frac{DC}{BD}$

$⇒ \frac{b}{c} + 1 = \frac{DC}{BD} + 1 \: \: \: [ Adding \: 1 \: to \: both \: sides ]$

$⇒ \frac{b}{c} = \frac{DC}{BD}$