Question

triangle ABC is a right angle triangle in which a b is equal to 3 cm BC is equal to 4 cm and angle b is equal to 90 degree BD is perpendicular from B on AC the circle through b c and d is draw construct the tangents from 8 to the given circle​

Answer 1

AB is tangent to Circle

Step-by-step explanation:

AB = 3 cm

BC = 4 cm

∠B = 90°

AC² = AB² + BC² = 3² + 4² = 25

=> AC = 5 cm

(1/2) * AB * BC = (1/2) * AC * BD

=> (1/2) * 3 * 4 = (1/2) * 5 * BD

=> BD = 2.4 cm

Now BD ⊥ AC => BD  ⊥ DC

=> Circle Passing through BDC    & ∠BDC = 90°

=> BC is Diameter of Circle

Take the mid point of BC

OB = OC  = 4/2 = 2 cm

Circle will be Drawn from O passing through B , D & C with radius = 2 cm

As OB is Radius

=> AB is tangent to Circle

Learn More

Construct Tangent

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