Math, asked by harshitabadgotte2007, 9 months ago

Triangle ABC is a right angled at A. AD is perpendicular to BC. If AB = 5cm, BC= 13cm and AC= 12cm, then find the area of triangle ABC. Also find the length of AD​

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Answered by Anonymous
2

Answer:

= 30cm^2

Step-by-step explanation:

Area of triangle = 1/2 x base x height

Base = 5cm , Height = 12cm

= 1/2 x 5 x 12

= 30 cm^2

Answered by me175
5

Answer:

AD = 60/13 cm.

Explanation:

Triangle ABC is right angled at A.

Therefore, we can say that BC is the hypotenuse.

Let AB be the base and AC the altitude of Triangle ABC.

Given, AB = 5 cm , BC = 13 cm and AC = 12 cm

Area of triangle ABC = 1/2 × base × altitude

= 1/2 × length of AB × length of AC

= 1/2 × 5 cm × 12 cm = 30 cm²

Hence, area of ∆ABC = 30 cm²

Area of Triangle ABC = 1/2 × length of AB × length of AC = 1/2 × length of BC × length of AD

= 5 cm × 12 cm = 13 cm × length of AD

= 60/13 = length of AD

Hence, the length of AD = 60/13 cm

Hope it helps!

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