Question

triangle ABC is a right angled triangle at C and CD perpendicular to AB.If angle B=40 then find 1)angle BAC
2)angle ACD 3) angle BCD

Answer 1

Hey friend, Here is your answer-
In the triangle ABC , 3. Angle BDC = 90°.........given
Therefore Angle CBD +BDC +BCD=180.......Sum of angles of triangle
40°+90°+BCD=180°
130°+BCD=180°
BCD=50°

2. Angle ACB=90°......given
Angle ACB=Angle ACD+BCD
90°=ACD+50°
Angle ACD=40°

1. Angle ABC=40°............(A-D-B)
ACB+ABC+BAC=180°............Sum of angles of triangle
Therefore 90°+40°+BAC=180°
130°+BAC=180°
BAC=50°

Hope it will help you friend.
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Answer 2

Answer:

Hey..!! ...Mate

Here is your answer in attachment

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